H=3x^2-5

Solution for H=3x^2-5 equation:

=3H^2-5

We move all terms to the left:

-(3H^2-5)=0

We get rid of parentheses

-3H^2+5=0

a = -3; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-3)·5
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{15}}{2*-3}=\frac{0-2\sqrt{15}}{-6}
=-\frac{2\sqrt{15}}{-6}
=-\frac{\sqrt{15}}{-3}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{15}}{2*-3}=\frac{0+2\sqrt{15}}{-6}
=\frac{2\sqrt{15}}{-6}
=\frac{\sqrt{15}}{-3}
$